Java quiz 06: Handling exceptions

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Handling Exceptions is one of the important concepts in Java programming language.
I try to make that concept clear in this simple program.
If you are not familiar with Exceptions, I recommend to read my article “Java exception handling using easy exercises” before trying this quiz.

Java quiz 6: Handling exceptions

Level: Normal

What is written to the standard output as the result of executing the following code?

public class MyException
{
  public static void main(String[] args)
  {
    int x = 0;
    int y = 4;
    try
    {
      System.out.print("a");
      y = y / x;
      System.out.print("b");
    }
    catch (ArithmeticException ae)
    {
      System.out.print("c");
    }
    finally
    {
      System.out.print("d");
    }
  }
}
Author: Sar Maroof

Select the correct answer.


Answer explanation

  1. Here is obviously an arithmetic exception occurs, because the statement y = y/x; divides y by 0.┬áIn the try block the first statement writes the letter “a” to the standard output, but the statement y = y/x; causes an arithmetic exception. Therefore the rest of the try block will be ignored.
  2. The type of the exception is an arithmetic exception. Therefore the catch block is executed and the statement System.out.print(“c”); writes the letter “c” to the standard output.
  3. If you read the article already, you know that the finally block is always executed. Therefore the statement System.out.print(“d”); writes the letter “d” to the standard output.
    So, the correct answer is option c.

 





Sar Maroof is a professional software development teacher, gives master classes and publishes technical articles. He is also an expert software developer and worked for several big as well as small companies and later as a freelancer.

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