Java quiz 09: How to handle exceptions?

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As a programmer you need to realize what kind of exceptions might occur in your code.
By handling the exceptions, you would avoid problems for the users of your program.
In the following example, passing some parameters to the method myMethod could cause exceptions. Therefore it is necessary to handle the exceptions that might occur.

Java quiz 9: How to handle exceptions?

Level: Hard

What is written to the standard output as the result of executing the following code?

public class MyException
{
  int[] arrayInt = new int[8];
  int nr = 3;

  public void myMethod(int i, int i2)
  {
    try
    {
      arrayInt[i] = i2;
      nr = i / i2;
      System.out.print("s");
    }
    catch (ArithmeticException ae)
    {
      System.out.print("t");
    }
    catch (ArrayIndexOutOfBoundsException ae)
    {
      System.out.print("x");
    }
  }
  public static void main(String[] args)
  {
    MyException me = new MyException();
    me.myMethod(8, 0);
    me.myMethod(7, 0);
  }
}
                                                                Author: Sar Maroof

Select the correct answer.


Answer explanation

  1. After creating the object me, the method myMethod(8, 0) is invoked. The parameter 8 is passed to the statement arrayInt[i] = i2; as follows: arrayInt[8] = 0.
    Since the eighth element of the array doesn’t exist, the exception ArrayIndexOutOfBoundsException is occured.
    Therefore the program writes “x” to the standard output.
  2. When the method myMethod(7, 0) is invoked, the statement nr = i / i2; divides 7 by zero. Dividing by zero causes ArithmeticException. Therefore, the program writes “t” to the standard output.
    So, this program writes xt to the standard output.

The correct answer is: f.





Sar Maroof is a professional software development teacher, gives master classes and publishes technical articles. He is also an expert software developer and worked for several big as well as small companies and later as a freelancer.

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